8=x^2/3

Solution for 8=x^2/3 equation:

8=x^2/3

We move all terms to the left:

8-(x^2/3)=0

We get rid of parentheses

-x^2/3+8=0

We multiply all the terms by the denominator


-x^2+8*3=0

We add all the numbers together, and all the variables

-1x^2+24=0

a = -1; b = 0; c = +24;
Δ = b2-4ac
Δ = 02-4·(-1)·24
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{6}}{2*-1}=\frac{0-4\sqrt{6}}{-2}
=-\frac{4\sqrt{6}}{-2}
=-\frac{2\sqrt{6}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{6}}{2*-1}=\frac{0+4\sqrt{6}}{-2}
=\frac{4\sqrt{6}}{-2}
=\frac{2\sqrt{6}}{-1}
$